Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises: 28

Answer

$2\sqrt[3]{12}$

Work Step by Step

RECALL: $\sqrt[3]{a} \cdot \sqrt[3]{b} = \sqrt[3]{a\cdot b}.$ Use the rule above to have $\sqrt[3]{6(16)} \\=\sqrt[3]{96} \\=\sqrt[3]{8(12)} \\=\sqrt[3]{2^3(12)} \\=2\sqrt[3]{12}.$
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