Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 371: 18



Work Step by Step

RECALL: $\sqrt{a} \cdot \sqrt{b} = \sqrt{a\cdot b}, a\gt 0, b \gt 0$ Use the rule above to have $\sqrt{50(75)} \\=\sqrt{3750} \\=\sqrt{625(6)} \\=\sqrt{25^3(6)} \\=25\sqrt{6}.$
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