Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 425: 93

Answer

$\sqrt[6]{144}$

Work Step by Step

Using $a^{m/n}=\sqrt[n]{a^m}$ and the laws of exponents, then, \begin{array}{l} \sqrt[]{3}\cdot\sqrt[3]{4} \\\\= 3^{\frac{1}{2}}\cdot4^{\frac{1}{3}} \\\\= 3^{\frac{3}{6}}\cdot4^{\frac{2}{6}} \\\\= (3^3\cdot4^2)^{\frac{1}{6}} \\\\= (9\cdot16)^{\frac{1}{6}} \\\\= (144)^{\frac{1}{6}} \\\\= \sqrt[6]{144} .\end{array}
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