Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 425: 103

Answer

$8\times2$

Work Step by Step

$16=8\times2$ We know that 8 is a perfect cube, because $2^{3}=8$.
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