Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set: 78

Answer

$\sqrt[4] (2y)$

Work Step by Step

$\sqrt[8] (4y^{2})=(4y^{2})^{\frac{1}{8}}=(2^{2}y^{2})^{\frac{1}{8}}=2^{\frac{2}{8}}y^{\frac{2}{8}}=2^{\frac{1}{4}}y^{\frac{1}{4}}=\sqrt[4] (2y)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.