Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 425: 88

Answer

$\sqrt[20]{a}$

Work Step by Step

Using $a^{m/n}=\sqrt[n]{a^m}$ and the laws of exponents, then, \begin{array}{l} \dfrac{\sqrt[4]{a}}{\sqrt[5]{a}} \\\\= \dfrac{a^{1/4}}{a^{1/5}} \\\\= a^{\frac{1}{4}-\frac{1}{5}} \\\\= a^{\frac{5}{20}-\frac{4}{20}} \\\\= a^{\frac{1}{20}} \\\\= \sqrt[20]{a^1} \\\\= \sqrt[20]{a} .\end{array}
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