Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 425: 56

Answer

$16x^{1/2}$

Work Step by Step

Using laws of exponents, then, \begin{array}{l} \dfrac{(2x^{1/5})^{4}}{x^{3/10}} \\\\= \dfrac{2^4x^{\frac{1}{5}\cdot4}}{x^{\frac{3}{10}}} \\\\= \dfrac{16x^{\frac{4}{5}}}{x^{\frac{3}{10}}} \\\\= 16x^{\frac{4}{5}-\frac{3}{10}} \\\\= 16x^{\frac{8}{10}-\frac{3}{10}} \\\\= 16x^{\frac{5}{10}} \\\\= 16x^{1/2} .\end{array}
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