Answer
$\sqrt[12]{b^5}$
Work Step by Step
Using $a^{m/n}=\sqrt[n]{a^m}$ and the laws of exponents, then,
\begin{array}{l}
\dfrac{\sqrt[3]{b^2}}{\sqrt[4]{b}}
\\\\=
\dfrac{b^{2/3}}{b^{1/4}}
\\\\=
b^{\frac{2}{3}-\frac{1}{4}}
\\\\=
b^{\frac{8}{12}-\frac{3}{12}}
\\\\=
b^{\frac{5}{12}}
\\\\=
\sqrt[12]{b^5}
.\end{array}
