Answer
$x^{-\frac{3}{4}}(1+3x^{\frac{4}{4}})=x^{-\frac{3}{4}}(1+3x)$
Work Step by Step
$x^{-\frac{3}{4}}+3x^{\frac{1}{4}}=x^{-\frac{3}{4}}(1)+x^{-\frac{3}{4}}(3x^{\frac{4}{4}})=x^{-\frac{3}{4}}(1+3x^{\frac{4}{4}})=x^{-\frac{3}{4}}(1+3x)$
In this problem, we make use of the product rule, which holds that $a^{m}\times a^{n}=a^{m+n}$.
For example, $x^{-\frac{3}{4}}\times x^{\frac{4}{4}}=x^{(-\frac{3}{4}+\frac{4}{4})}=x^{\frac{1}{4}}$
