Answer
$\sqrt[6] (y^{5})$
Work Step by Step
$\sqrt[3] (y^{2})\times\sqrt[6] y=y^{\frac{2}{3}}\times y^{\frac{1}{6}}$
We can further simplify by using the product rule, which holds that $a^{m}\times a^{n}=a^{m+n}$.
$y^{\frac{2}{3}}\times y^{\frac{1}{6}}=y^{(\frac{2}{3}+\frac{1}{6})}=y^{(\frac{4}{6}+\frac{1}{6})}=y^{\frac{5}{6}}=\sqrt[6] (y^{5})$
