Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set: 75

Answer

$\sqrt[3] 2$

Work Step by Step

$\sqrt[6] (4)=4^{\frac{1}{6}}=(2^{2})^{\frac{1}{6}}=2^{\frac{2}{6}}=2^{\frac{1}{3}}=\sqrt[3] 2$
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