Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set: 77

Answer

$2\sqrt x$

Work Step by Step

$\sqrt[4] (16x^{2})=(16x^{2})^{\frac{1}{4}}=(4^{2}x^{2})^{\frac{1}{4}}=4^{\frac{2}{4}}x^{\frac{2}{4}}=4^{\frac{1}{2}}x^{\frac{1}{2}}=2\sqrt x$ We know that $4^{\frac{1}{2}}=2$, because $2^{2}=4$.
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