Answer
$\text{ approximately }1509.0 \text{ calories}$
Work Step by Step
Using the given function, $
B(w)=70w^{3/4}
,$ then
\begin{array}{l}\require{cancel}
B(w)=70(60)^{3/4}
\\
B(w)=70(21.558246717785053362090056351417)
\\
B(w)=1509.0772702449537353463039445992
\\
B(w)\approx1509.0
.\end{array}
Hence, the BMR, $B(w),$ for a person who weighs $60$ kilogram is $
\text{ approximately }1509.0 \text{ calories}
.$
