Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 46

Answer

$\frac{y^{2}}{x}$

Work Step by Step

We are given the expression $(x^{-3}y^{6})^{\frac{1}{3}}$. We can use the power rule, which holds that $(a^{m})^{n}=a^{m\times n}$ (where a is a real number, and m and n are integers). $(x^{-3}y^{6})^{\frac{1}{3}}=x^{(-3\times\frac{1}{3})}y^{(6\times\frac{1}{3})}=x^{-1}y^{2}=\frac{y^{2}}{x}$
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