## Intermediate Algebra (6th Edition)

$\frac{1}{b}$
We are given the expression $\frac{b^{\frac{1}{3}}}{b^{\frac{4}{3}}}$. To simplify, we can use the quotient rule, which holds that $\frac{a^{m}}{a^{n}}=a^{m-n}$ (where a is a nonzero real number, and m and n are integers). $\frac{b^{\frac{1}{3}}}{b^{\frac{4}{3}}}=b^{(\frac{1}{3}-\frac{4}{3})}=b^{-\frac{3}{3}}=b^{-1}=\frac{1}{b}$