Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 23

Answer

y

Work Step by Step

$\sqrt[5] (y^{5})=y$ We know that $\sqrt[5] (y^{5})=y$ because $(y^{5})^\frac{1}{5}=(y)^{5\times\frac{1}{5}}=y$ We do not need absolute value bars around the result, because the index of the radical is odd in this case.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.