#### Answer

-x

#### Work Step by Step

$-\sqrt[5] (x^{5})=-(x)=-x$
We know that $\sqrt[5] (x^{5})=x$ because $(x^{5})^\frac{1}{5}=(x)^{5\times\frac{1}{5}}=x$
In this case, we are taking the opposite of $\sqrt[5] (x^{5})$.
We do not need absolute value bars around the result, because the index of the radical is odd in this case.