Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 37

Answer

$x^{\frac{2}{3}}$

Work Step by Step

We are told on page 419 that $\sqrt[n] (a^{m})=a^{\frac{m}{n}}$ (where m and n are positive integers greater than 1 with $\frac{m}{n}$ in simplest form and $\sqrt[n] a$ is a real number). Therefore, $\sqrt[3] (x^{2})=x^{\frac{2}{3}}$
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