## Intermediate Algebra (6th Edition)

$-\frac{1}{4}$
$(-64)^{-\frac{1}{3}}=\frac{1}{(-64)^{\frac{1}{3}}}=\frac{1}{\sqrt[3] (-64)}=\frac{1}{(-4)}=-\frac{1}{4}$ We know that $\sqrt[3] (-64)=-4$, because $(-4)^{3}=-4\times-4\times-4=-64$.