Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 28

Answer

$-\frac{1}{3}$

Work Step by Step

$(-\frac{1}{27})^\frac{1}{3}=\sqrt[3] (-\frac{1}{27})=-\frac{1}{3}$ We know this because $(-\frac{1}{3})^{3}=-\frac{1}{3}\times-\frac{1}{3}\times-\frac{1}{3}=-\frac{1}{27}$
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