Answer
-5
Work Step by Step
$\sqrt[5] ((-5)^{5})=-5$, because $((-5)^{5})^\frac{1}{5}=(-5)^{5\times\frac{1}{5}}=(-5)^{1}=-5$
We do not need absolute value bars around the result, because the index of the radical is odd in this case.
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Review - Page 468: 18
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