Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 42

Answer

$\frac{1}{\sqrt (x+2y)}$

Work Step by Step

We are told on page 419 that $a^{\frac{m}{n}}=\sqrt[n] (a^{m})$ (where m and n are positive integers greater than 1 with $\frac{m}{n}$ in simplest form and $\sqrt[n] a$ is a real number). Therefore, $(x+2y)^{-\frac{1}{2}}=\frac{1}{(x+2y)^{\frac{1}{2}}}=\frac{1}{\sqrt (x+2y)}$
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