## Intermediate Algebra (6th Edition)

2, $\sqrt[3] 17$
We are given the function $g(x)=\sqrt[3] (x-3)$. $g(11)=\sqrt[3] (11-3)=\sqrt[3] 8=2$ We know this because $2^{3}=8$. $g(20)=\sqrt[3] (20-3)=\sqrt[3] 17$