Answer
$\frac{x^{6}}{6y}$
Work Step by Step
$\sqrt (\frac{x^{12}}{36y^{2}})=\sqrt (x^{12})\times\sqrt (\frac{1}{36y^{2}})=x^{6}\times\frac{1}{6y}=\frac{x^{6}}{6y}$
We know that $\sqrt (x^{12})=x^{6}$, because $(x^{6})^{2}=x^{6\times2}=x^{12}$.
We know that $\sqrt (\frac{1}{36y^{2}})=\frac{1}{6y}$, because $(\frac{1}{6y})^{2}=\frac{1}{6y}\times\frac{1}{6y}=\frac{1}{36y^{2}}$.
