Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 468: 43

Answer

$a^{\frac{13}{6}}$

Work Step by Step

$a^{\frac{1}{3}}a^{\frac{4}{3}}a^{\frac{1}{2}}=a^{(\frac{1}{3}+\frac{4}{3}+\frac{1}{2})}=a^{(\frac{2}{6}+\frac{8}{6}+\frac{3}{6})}=a^{\frac{13}{6}}$
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