Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 33

Answer

not a real number

Work Step by Step

$(-25)^{\frac{5}{2}}=\sqrt (-25)^{5}=\sqrt (-25\times-25\times-25\times-25\times-25)=\sqrt (-25)\times\sqrt (-25)\times\sqrt(-25)\times\sqrt(-25)\times\sqrt(-25)$ We cannot not simplify this any further, as $\sqrt (-25)$ is not a real number. We cannot find a number $a$ such that $a^{2}=-25$.
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