Answer
$\frac{1}{3}$
Work Step by Step
$(\frac{1}{81})^\frac{1}{4}=\sqrt[4] (\frac{1}{81})=\frac{1}{3}$
We know this because $(\frac{1}{3})^{4}=\frac{1}{3}\times\frac{1}{3}\times\frac{1}{3}\times\frac{1}{3}=\frac{1}{81}$
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