College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises: 67

Answer

$x=\frac{13}{12}$

Work Step by Step

$\log_{5}(x+1)-\log_{5}(x-1)=2$ $\log_{5}(\frac{x+1}{x-1})=2$ $5^2=\frac{x+1}{x-1}$ $25(x-1)=x+1$ $25x-25=x+1$ $24x=26$ $x=\frac{26}{24}=\frac{13}{12}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.