Answer
$x=1$
Work Step by Step
We need to solve:
$2^{x}-10(2^{-x})+3=0$
We multiply through by $2^x$:
$2^x(2^{x}-10(2^{-x})+3=0)$
$2^{2x}-10+3* 2^{x}=0$
$(2^{x}+5)(2^{x}-2)=0$
$(2^{x}+5)=0$ or $(2^{x}-2)=0$
$2^x=-5$ or $2^x=2$
$x=\log_2 -5$=no solution or $x=\log_2 2=1$