Answer
$x=4$ or $x=2$
Work Step by Step
$2\log x=\log 2+\log(3x-4)$
$\log(x^{2})=\log(2(3x-4))$
$\log(x^{2})=\log(6x-8)$
$x^{2}=6x-8$
$x^{2}-6x+8=0$
$(x-4)(x-2)=0$
$(x-4)=0$ or $(x-2)=0$
$x=4$ or $x=2$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 404: 51
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