Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 404: 18

(a) $x=\frac{1}{12}\ln(\frac{17}{2})$ (b) $x\approx 0.178339$

(a) We need to solve: $2e^{12x}=17$ $e^{12x}=\frac{17}{2}$ We take the log of both sides and use log rules to simplify: $12x=\ln(\frac{17}{2})$ $x=\frac{1}{12}\ln(\frac{17}{2})$ (b) We solve using a calculator: $x\approx 0.178339$