Answer
$x=1$
Work Step by Step
$\ln(x-\frac{1}{2})+\ln 2=2\ln x$
$\ln((x-\frac{1}{2})*2)=\ln x^{2}$
$2x-1=x^{2}$
$x^{2}-2x+1=0$
$(x-1)^{2}=0$
$x-1=0$
$x=1$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 404: 52
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