Answer
$x=0$ or $x=\ln 2\approx 0.6931$
Work Step by Step
We need to solve:
$e^{2x}-3e^{x}+2=0$
We factor:
$(e^{x}-1)(e^{x}-2)=0$
$e^{x}-1=0$ or $e^{x}-2=0$
$e^{x}=1$ or $e^x=2$
$x=\ln 1$ or $x=\ln 2$
$x=0$ or $x=\ln 2\approx 0.6931$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 404: 39
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