Answer
$x=0$
$x=\frac{4}{3}$
Work Step by Step
We need to solve:
$4x^{3}e^{-3x}-3x^{4}e^{-3x}=0$
We factor:
$x^{3}e^{-3x}(4-3x)=0$
$x^{3}=0$ or $e^{-3x}=0$ or $(4-3x)=0$
$x=0$ or $x=-\frac{1}{3}\ln 0$=no solution, or $x=\frac{4}{3}$
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