College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 404: 71

Answer

$x=\left\{0, 1.14\right\}$

Work Step by Step

To solve the given equation graphically, you have to treat each side of the equation as a function. Thus, using a graphing utility, graph the functions: $y=x^3-x$ (the blue graph) $y=\log(x+1)$ (the red graph) (refer to the image below for the graph. The point/s where the graphs intersect are the points where $x^3-x=\log(x+1)$. The x-coordinates of these point are the solutions to the given equation. Note that the graphs intersect at the points $(0, 0)$ and $(1.136, 0.33)$. The x-coordinates of these points are $0$ and $1.136$. Rounded-off to two decimal places, the solution to the given equation is: $x=\left\{0, 1.14\right\}$
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