College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 404: 11

Answer

(a) $x = 2\cdot \log{5}$ (b) $x \approx 1.397940$

Work Step by Step

(a) Take the common logarithm of both sides to obtain: $\log{10^x} = \log{25}$ Use the rule $\log{10^n} = n$ to obtain: $x = \log{25} \\x=\log{(5^2)}$ Use the rule $\log{(a^n)} = n\log{a}$ to obtain: $x = 2\cdot \log{5}$ (b) Use a calculator to evaluate the answer and have: $x \approx 1.397940$
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