Answer
$x=\frac{1}{2}\ln 3\approx 0.5493$
Work Step by Step
We need to solve:
$e^{4x}+4e^{2x}-21=0$
We factor:
$(e^{2x}+7)(e^{2x}-3)=0$
$(e^{2x}+7)=0$ or $(e^{2x}-3)=0$
$e^{2x}=-7$ or $e^{2x}=3$
$2x=\ln(-7)$ or $2x=\ln 3$
$x=\frac{1}{2}\ln(-7)$=no solution or $x=\frac{1}{2}\ln 3\approx 0.5493$