Answer
$x=3$
Work Step by Step
$\log_{4}(x+2)+\log_{4}3=\log_{4}5+\log_{4}(2x-3)$
$\log_{4}((x+2)*3)=\log_{4}(5*(2x-3))$
$\log_{4}(3x+6)=\log_{4}(10x-15)$
$3x+6=10x-15$
$7x=21 $
$x=\frac{21}{7}=3$
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