College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 404: 54

Answer

$x=3$

Work Step by Step

$\log_{4}(x+2)+\log_{4}3=\log_{4}5+\log_{4}(2x-3)$ $\log_{4}((x+2)*3)=\log_{4}(5*(2x-3))$ $\log_{4}(3x+6)=\log_{4}(10x-15)$ $3x+6=10x-15$ $7x=21 $ $x=\frac{21}{7}=3$
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