Answer
$x=\left\{-3, 3\right\}$
Work Step by Step
Use the property $a^m = a^n \longrightarrow m=n$ to obtain:
$\begin{array}{ccc}
&x^2&=&9
\\&\sqrt{x}&=&\pm\sqrt{9}
\\&x&=&\pm3
\end{array}$
Thus, the solutions are:$x=\left\{-3, 3\right\}$.
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 404: 4
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