College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 404: 70

Answer

$x=\left\{0.01, 1.47\right\}$

Work Step by Step

To solve the given equation graphically, you have to treat each side of the equation as a function. Thus, using a graphing utility, graph the functions: $y=\log{x}$ (the blue graph) $y=x^2-2$ (the red graph) (refer to the image below for the graph. The point/s where the graphs intersect are the points where $\log{x}=x^2-2$. The x-coordinates of these point are the solutions to the given equation. Note that the graphs intersect at the points $(0.01, -2)$ and $(1.472, 0.168)$. The x-coordinates of these points are $0.01$ and $1.472$. Rounded-off to two decimal places, the solution to the given equation is: $x=\left\{0.01, 1.47\right\}$
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