College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 404: 7

Answer

The solution is $x=-3$.

Work Step by Step

Use the property $a^m = a^n \longrightarrow m=n$ to obtain: $\begin{array}{ccc} &2x-3&=&6+5x \\&2x-3-2x&=&6+5x-2x \\&-3&=&6+3x \\&-3-6&=&6+3x-6 \\&-9&=&3x \\&-9&=&3x \\&\dfrac{-9}{3} &= &\dfrac{3x}{3} \\&-3&=&x \end{array}$ Thus, the solution is $x=-3$.
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