## Physics (10th Edition)

Let t = time elapsed since the bear was 26m behind $distance_{bear}$ = average speed $\times$ time = 6.0t d =$distance_{tourist}$ = average speed $\times$ time = 4.0t 6.0t $\leq$ 4.0t + 26 2t $\leq$ 26 t $\leq$ 13 $d_{min}$ = 4.0$t_{min}$ = 4.0 (13) = 52 m