Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems - Page 48: 15

Answer

a) 0 $m/s^{2}$ b) -14 $m/s^{2}$

Work Step by Step

a) $acceleration$ = $\frac{v-u}{t}$ = $\frac{82-82}{t}$ = $\frac{0}{t}$ = 0 $m/s^{2}$ Travelling at a constant velocity (no change in velocity) hence acceleration is 0 b) $acceleration$ = $\frac{v-u}{t}$ = $\frac{-82-82}{12}$ = $\frac{-164}{12}$ $\approx$ -14 $m/s^{2}$
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