Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems - Page 48: 13

Answer

2.1 s

Work Step by Step

$tan( \theta )$ = $\frac{opposite}{adjacent}$ $tan(12^{\circ})$ = $\frac{0.9}{x}$ $x$ = $\frac{0.9}{tan(12^{\circ})}$ distance travelled = $\frac{0.9}{tan(12^{\circ})}$ + 2.0 $\approx$ 6.234 m time = distance / speed $\approx$ 6.234 / 3.0 $\approx$ 2.1 s
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