## Physics (10th Edition)

distance = speed $\times$ time a) $d_{1}$ = 7.2 $\times$ (22 $\times$ 60) = 9504 m $d_{2}$ = 5.1 $\times$ (36 $\times$ 60) = 11 016 m $d_{3}$ = 13 $\times$ (8 $\times$ 60) = 6240 m Total distance = 9504 + 11 016 + 6240 = 26 760 m b) Total time = (22 + 36 + 8) $\times$ 60 = 3960 s Average velocity = displacement / time = 26 760 / 3960 = 6.76 m/s due north