## Physics (10th Edition)

$a=\frac{v-u}{t}$ a) $a_{j}=\frac{3.0-0}{2.0}$ = 1.5 $m/s^{2}$ b) $a_{c}=\frac{41.0-38.0}{2.0}$ = 1.5 $m/s^{2}$ c) $x=\frac{1}{2}(u+v)t$ $x_{j}=\frac{1}{2}(0+3.0)(2.0)$ = 3.0 m $x_{c}=\frac{1}{2}(38.0+41.0)(2.0)$ = 79 m Car travels 79-3.0 = 76 m further