## Physics (10th Edition)

Published by Wiley

# Chapter 2 - Kinematics in One Dimension - Problems: 18

#### Answer

a) + 2.8 m/s b) + 2.8 m/s

#### Work Step by Step

v = u + at a) v = u + at = (0) + (2.3)(1.2) = 2.76 $\approx$ +2.8 m/s b) v = u + at = (2.76) + (0)t = 2.76 $\approx$ +2.8 m/s Since acceleration is 0 after 1.2 s, the velocity remains constant

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