Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems: 8

Answer

64.0 s

Work Step by Step

distance in m = 10.0 $\times$ 1000 = 1.00 $\times$$10^{4}$ $time_{younger}$ = distance / average speed = (1.00 $\times$$10^{4}$) / 4.39 $\approx$ 2.2779 $\times$$10^{3}$ s $time_{older}$ = distance / average speed = (1.00 $\times$$10^{4}$) / 4.27 $\approx$ 2.3419 $\times$$10^{3}$ s 2.3419 $\times$$10^{3}$ - 2.2779 $\times$$10^{3}$ $\approx$ 64.0 s
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