Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems: 23

Answer

Cycle A was initially travelling 8 m/s faster

Work Step by Step

u = v - at $u_{A}$ = v - (2.0)(4) = v-8 $u_{B}$ = v - (4.0)(4) = v-16 Difference in initial speeds = (v-8) - (v-16) = 8 m/s
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