## Physics (10th Edition)

Let due north be the positive direction Let T = total time $x_{n}$ = $v_{n}$$t_{n} = (27)(\frac{3}{4}T) = \frac{81}{4}T m x_{s} = v_{s}$$t_{s}$ = (-17)($\frac{1}{4}$T) = -$\frac{17}{4}$T m Average velocity = displacement / time = ($\frac{81}{4}$T - $\frac{17}{4}$T) / T = +16 m/s 16 m/s due north